Question

The stepwise formation of ${\left[\mathrm{Cu}{\left({\mathrm{NH}}_3\right)}_4\right]}^{2+}$ is given below:

${\mathrm{Cu}}^{2+}+{\mathrm{NH}}_3\stackrel{{\mathrm{K}}_1}{\rightleftharpoons }{\left[\mathrm{Cu}\left({\mathrm{NH}}_3\right)\right]}^{2+}$

${\left[\mathrm{Cu}\left({\mathrm{NH}}_3\right)\right]}^{2+}+{\mathrm{NH}}_3\stackrel{{\mathrm{K}}_2}{\rightleftharpoons }{\left[\mathrm{Cu}{\left({\mathrm{NH}}_3\right)}_2\right]}^{2+}$

${\left[\mathrm{Cu}{\left({\mathrm{NH}}_3\right)}_2\right]}^{2+}+{\mathrm{NH}}_3\stackrel{{\mathrm{K}}_3}{\rightleftharpoons }{\left[\mathrm{Cu}{\left({\mathrm{NH}}_3\right)}_3\right]}^{2+}$

${\left[\mathrm{Cu}{\left({\mathrm{NH}}_3\right)}_3\right]}^{2+}+{\mathrm{NH}}_3\stackrel{{\mathrm{K}}_4}{\rightleftharpoons }{\left[\mathrm{Cu}{\left({\mathrm{NH}}_3\right)}_4\right]}^{2+}$

The value of stability constants ${\mathrm{K}}_1, {\mathrm{K}}_2, {\mathrm{K}}_3$ and ${\mathrm{K}}_4$ are ${10}^4, 1.58\times {10}^3, 5\times {10}^2$ and ${10}^2$ respectively. The overall equilibrium constants for dissociation of ${\left[\mathrm{Cu}{\left({\mathrm{NH}}_3\right)}_4\right]}^{2+}$ is $x\times {10}^{-12}.$ The value of $\mathrm{x}$ is _____ (Rounded off to the nearest integer)

JEE Main 2021 (24 Feb Shift 1)

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Question

Consider the following reaction:
${\mathrm{N}}_2{\mathrm{O}}_4\left(g\right)=2{\mathrm{NO}}_2\left(\mathrm{g}\right): \Delta {\mathrm{H}}^0=+58\mathrm{k}$
For each of the following cases $(\mathrm{a}, \mathrm{b})$, the direction in which the equilibrium shifts is:
(a) Temperature is decreased.
(b) Pressure is increased by adding ${\mathrm{N}}_2$ at constant T.

JEE Main 2020 (05 Sep Shift 1)

Options

• A: (a) towards product, (b) towards reactant
• B: (a) towards reactant, (b) towards product
• C: (a) towards reactant, (b) no change
• D: (a) towards product, (b) no change

Question

The equilibrium constant for the reaction \(\mathrm{SO}_3(\mathrm{g}) \rightleftharpoons \mathrm{SO}_2(\mathrm{~g})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g})\) is \(\mathrm{K}_{\mathrm{c}}=4.9 \times 10^{-2}\). The value of \(\mathrm{K}_{\mathrm{c}}\) for the reaction given below is \(2 \mathrm{SO}_2(\mathrm{~g})+\mathrm{O}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{SO}_3(\mathrm{~g})\) is :

JEE Main 2024 (04 Apr Shift 2)

Options

• A: 4.9
• B: 49
• C: 41.6
• D: 416

Question

The reaction rate for the reaction

${\left[{\mathrm{PtCl}}_4\right]}^{2-}+{\mathrm{H}}_2\mathrm{O}\rightleftharpoons {\left[\mathrm{Pt}\left({\mathrm{H}}_2\mathrm{O}\right){\mathrm{Cl}}_3\right]}^{-}+{\mathrm{Cl}}^{-}$

was measured as a function of concentrations of different species. It was observed that

$\frac{-\mathrm{d}\left[{\left[{\mathrm{PtCl}}_4\right]}^{2-}\right]}{\mathrm{dt}}=4.8\times {10}^{-5}\left[{\left[{\mathrm{PtCl}}_4\right]}^{2-}\right]-2.4\times {10}^{-3}\left[{\left[\mathrm{Pt}\left({\mathrm{H}}_2\mathrm{O}\right){\mathrm{Cl}}_3\right]}^{-}\right]\left[{\mathrm{Cl}}^{-}\right]$

where square brackets are used to denote molar concentrations. The equilibrium constant

${\mathrm{K}}_{\mathrm{c}}=X$(Nearest integer)

Value of $\frac{1}{X} is$ (question is modified.)

JEE Main 2021 (26 Aug Shift 2)

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Question

For a reaction at equilibrium

 $\mathrm{A}\left(\mathrm{g}\right)\rightleftharpoons \mathrm{B}\left(\mathrm{g}\right)+\frac{1}{2}\mathrm{C}\left(\mathrm{g}\right)$

 the relation between dissociation constant $\left(\mathrm{K}\right)$, degree of dissociation $\left(\mathrm{\alpha }\right)$ and equilibrium pressure $\left(\mathrm{p}\right)$ is given by :

JEE Main 2022 (24 Jun Shift 1)

Options

• A: $\mathrm{K}=\frac{{\mathrm{\alpha }}^{\frac{3}{2}}{\mathrm{p}}^{\frac{1}{2}}}{{\left(2+\mathrm{\alpha }\right)}^{\frac{1}{2}}\left(1-\mathrm{\alpha }\right)}$
• B: $\mathrm{K}=\frac{{\mathrm{\alpha }}^{\frac{1}{2}}{\mathrm{p}}^{\frac{3}{2}}}{{\left(1+\frac{3}{2}\mathrm{\alpha }\right)}^{\frac{1}{2}}{\displaystyle \left(1-\mathrm{\alpha }\right)}}$
• C: $\mathrm{K}=\frac{{\left(\mathrm{\alpha p}\right)}^{\frac{3}{2}}}{{\left(1+\frac{3}{2}\mathrm{\alpha }\right)}^{\frac{1}{2}}\left(1-\mathrm{\alpha }\right)}$
• D: $\mathrm{K}=\frac{{\left(\mathrm{\alpha p}\right)}^{\frac{3}{2}}}{\left(1+\mathrm{\alpha }\right){\left(1-\mathrm{\alpha }\right)}^{\frac{1}{2}}}$

Question

At \(-20^{\circ} \mathrm{C}\) and \(1 \mathrm{~atm}\) pressure, a cylinder is filled with equal number of \(\mathrm{H}_2, \mathrm{I}_2\) and \(\mathrm{HI}\) molecules for the reaction \(\mathrm{H}_2(\mathrm{~g})+\mathrm{I}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{HI}(\mathrm{g})\), the \(\mathrm{K}_{\mathrm{p}}\) for the process is \(x \times 10^{-1}\). \(\mathrm{x}=\) _____ [Given : \(\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\)]

JEE Main 2024 (06 Apr Shift 1)

Options

• A: 0.01
• B: 10
• C: 2
• D: 1

Question

$A_{\left(g\right)}\rightleftharpoons B_{\left(g\right)}+\frac{C}{2^{\left(g\right)}}$. The correct relationship between $K_P, \alpha$ and equilibrium pressure $P$ is

JEE Main 2024 (31 Jan Shift 2)

Options

• A: ${\mathrm{K}}_{\mathrm{P}}=\frac{{\mathrm{\alpha }}^{\frac{1}{2}}{\mathrm{P}}^{\frac{1}{2}}}{{\left(2+\mathrm{\alpha }\right)}^{\frac{1}{2}}}$
• B: ${\mathrm{K}}_{\mathrm{P}}=\frac{{\mathrm{\alpha }}^{\frac{3}{2}}{\mathrm{P}}^{\frac{1}{2}}}{{\left(2+\mathrm{\alpha }\right)}^{\frac{1}{2}}\left(1-\mathrm{\alpha }\right)}$
• C: ${\mathrm{K}}_{\mathrm{P}}=\frac{{\mathrm{\alpha }}^{\frac{1}{2}}{\mathrm{P}}^{\frac{3}{2}}}{{\left(2+\mathrm{\alpha }\right)}^{\frac{3}{2}}}$
• D: ${\mathrm{K}}_{\mathrm{P}}=\frac{{\mathrm{\alpha }}^{\frac{1}{2}}{\mathrm{P}}^{\frac{1}{2}}}{{\left(2+\mathrm{\alpha }\right)}^{\frac{3}{2}}}$

Question

$4.0$ moles of argon and $5.0$ moles of ${\mathrm{PCl}}_5$ are introduced into an evacuated flask of $100$ litre capacity at $610 \mathrm{K}$. The system is allowed to equilibrate. At equilibrium, the total pressure of mixture was found to be $6.0 \mathrm{atm}$. The ${\mathrm{K}}_{\mathrm{p}}$ for the reaction is [Given : $\mathrm{R}=0.082 \mathrm{L}$ atm ${\mathrm{K}}^{-1}{ \mathrm{mol}}^{-1}$ ]

JEE Main 2022 (29 Jun Shift 2)

Options

• A: $2.25$
• B: $6.24$
• C: $12.13$
• D: $15.24$

Question

The standard free energy change $\left(\mathrm{\Delta G}°\right)$ for $50\%$ dissociation of ${\mathrm{N}}_2{\mathrm{O}}_4$ into ${\mathrm{NO}}_2$ at $27 °\mathrm{C}$ and $1 \mathrm{atm}$ pressure is $-\mathrm{x} \mathrm{J}{ \mathrm{mol}}^{-1}$. The value of $\mathrm{x}$ is $-..... \mathrm{J}$. (Nearest Integer)

[Given : $\mathrm{R}=8.31 \mathrm{J}{ \mathrm{K}}^{-1}{ \mathrm{mol}}^{-1}, \log 1.33=0.1239 \ln 10=2.3$]

JEE Main 2022 (25 Jun Shift 1)

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Question

The effect of addition of helium gas to the following reaction in equilibrium state at constant volume, is :
${\mathrm{PCI}}_5( \mathrm{g})\rightleftharpoons {\mathrm{PCl}}_3( \mathrm{g})+{\mathrm{Cl}}_2( \mathrm{g})$

JEE Main 2023 (01 Feb Shift 2)

Options

• A:  the equilibrium will shift in the forward direction and more of ${\mathrm{Cl}}_2$ and ${\mathrm{PCl}}_3$ gases will be produced.
• B: the equilibrium will go backward due to suppression of dissociation of ${\mathrm{PCl}}_5$.
• C:  helium will deactivate ${\mathrm{PCl}}_5$ and reaction will stop.
• D:  addition of helium will not affect the equilibrium.

Question

The equilibrium composition for the reaction 

${\mathrm{PCl}}_3+{\mathrm{Cl}}_2\underset{}{\rightleftharpoons }{\mathrm{PCl}}_5$ at $298 \mathrm{K}$ is given below:

${\left[{\mathrm{PCl}}_3\right]}_{\mathrm{eq}}=0.2 \mathrm{mol} {\mathrm{L}}^{-1}, {\left[{\mathrm{Cl}}_2\right]}_{\mathrm{eq}}=0.1 \mathrm{mol} {\mathrm{L}}^{-1}, {\left[{\mathrm{PCl}}_5\right]}_{\mathrm{eq}}=0.40 \mathrm{mol} {\mathrm{L}}^{-1}$

If $0.2 \mathrm{mol}$ of ${\mathrm{Cl}}_2$ is added at the same temperature, the equilibrium concentrations of ${\mathrm{PCl}}_5$ is _____ $\times {10}^{–2} \mathrm{mol} {\mathrm{L}}^{–1}$

Given: ${\mathrm{K}}_{\mathrm{c}}$ for the reaction at $298 \mathrm{K}$ is $20$

JEE Main 2023 (06 Apr Shift 2)

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Question

For the reaction ${\mathrm{N}}_2{\mathrm{O}}_4( \mathrm{g})\rightleftharpoons 2{\mathrm{NO}}_2( \mathrm{g})$, ${\mathrm{K}}_{\mathrm{p}}=0.492 \mathrm{atm}$ at $300 \mathrm{K}.{\mathrm{K}}_{\mathrm{c}}$ for the reaction at same temperature is $\_\_\_\_\_\_\times {10}^{-2}$. (Given :$\mathrm{R}=0.082 \mathrm{L} \mathrm{atm} {\mathrm{mol}}^{-1} {\mathrm{K}}^{-1}$)

JEE Main 2024 (29 Jan Shift 1)

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Question

Consider the reaction ${\mathrm{N}}_2{\mathrm{O}}_4( \mathrm{g})\rightleftharpoons 2{\mathrm{NO}}_2( \mathrm{g})$ The temperature at which ${\mathrm{K}}_{\mathrm{C}}=20.4$ and ${\mathrm{K}}_{\mathrm{P}}=600.1,$ is ______ $\mathrm{K}$. (Round off to the Nearest Integer). [Assume all gases are ideal and $\mathrm{R}=0.0831 \mathrm{L}$ bar $\left.{\mathrm{K}}^{-1}{ \mathrm{mol}}^{-1}\right]$

JEE Main 2021 (17 Mar Shift 2)

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Question

For the given reaction, choose the correct expression of ${\mathrm{K}}_{\mathrm{C}}$ from the following:

${{\mathrm{Fe}}^{3+}}_{\left(\mathrm{aq}\right)}+{{\mathrm{SCN}}^{-}}_{\left(\mathrm{aq}\right)}\rightleftharpoons (\mathrm{FeSCN}{{)}^{2+}}_{\left(\mathrm{aq}\right)}$

JEE Main 2024 (31 Jan Shift 1)

Options

• A: $K_C=\frac{\left[FeSC{N}^{2+}\right]}{\left[F{e}^{3+}\right]\left[SC{N}^{-}\right]}$
• B: $K_C=\frac{\left[F{e}^{3+}\right]\left[SC{N}^{-}\right]}{\left[FeSC{N}^{2+}\right]}$
• C: $K_C=\frac{\left[FeSC{N}^{2+}\right]}{{\left[F{e}^{3+}\right]}^2{\left[SC{N}^{-}\right]}^2}$
• D: $K_C=\frac{{\left[FeSC{N}^{2+}\right]}^2}{\left[F{e}^{3+}\right]\left[SC{N}^{-}\right]}$

Question

At $1990 \mathrm{K}$ and $1 \mathrm{atm}$ pressure, there are equal number of ${\mathrm{Cl}}_2$ molecules and $\mathrm{Cl}$ atoms in the reaction mixture. The value of ${\mathrm{K}}_{\mathrm{p}}$ for the reaction ${\mathrm{Cl}}_{2\left(\mathrm{g}\right)}=2{\mathrm{Cl}}_{\left(\mathrm{g}\right)}$ under the above conditions is $x\times {10}^{-1}.$ The value of $\mathrm{x}$ is______(Rounded off to the nearest integer)

JEE Main 2021 (24 Feb Shift 1)

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